650 lines
15 KiB
JSON
650 lines
15 KiB
JSON
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],
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"script": "#You do not need to use script input node. It however has some +es. For example faster repeated execution of workflow since transformations needed for code to run happen only once, not for each change of math node input.\n#Also you get line numbers so searching for error is easier\n# there are some input variables- V... for value input F... for float input. \n# Semicolon is used to separate commands. This line inverts image we sent to V0 since F0 = 1.\nt = F0-V0;\n# last expression determines output of the node. It does not have to be just variable as here. Ve could just put the F0-V0 as the only line\nt\n\n# If you see ValueError: Syntax error in expression at line 6, col 0: no viable alternative at input 't=F0-V0t' or something simillar, you forgot a semicolon"
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{
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"name": "FLOAT",
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"type": "FLOAT",
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"name": "IMAGE",
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"name": "SYNTAX_TREE",
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"type": "SYNTAX_TREE",
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"/*\nThere is a lot defined functions. Here I will overlay image and inverse of it. I will flip the inverse of inverse so it does not end up grey. There is overlay function but that is overkill here\n*/\ntrue_color = 1-V0;\nflipped = flip(true_color,1); # image is [batch, height, width, color plane]\nprint(\"Max of compound image: \"+smax(V0+flipped)); # We print the maximum value to console (smax() reduces dimensions, tmax() goes value-by-value)\nV0+flipped\n# Normally we should divide it by 2 to not blow out everything to white but here we do not do that"
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],
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"script": "/*\nThere is a lot defined functions. Here I will overlay image and inverse of it. I will flip the inverse of inverse so it does not end up grey. There is overlay function but that is overkill here\n*/\ntrue_color = 1-V0;\nflipped = flip(true_color,1); # image is [batch, height, width, color plane]\nprint(\"Max of compound image: \"+smax(V0+flipped)); # We print the maximum value to console (smax() reduces dimensions, tmax() goes value-by-value)\nV0+flipped\n# Normally we should divide it by 2 to not blow out everything to white but here we do not do that"
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}
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{
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{
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"name": "images",
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"type": "IMAGE",
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"link": 7
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}
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],
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"outputs": [
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{
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"name": "images",
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"type": "IMAGE",
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"links": [
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8
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"properties": {
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"Node name for S&R": "PreviewImage"
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"label": "V0",
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"name": "V.V0",
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"type": "IMAGE",
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"link": 8
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"label": "F1",
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"name": "F.F1",
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"shape": 7,
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"type": "FLOAT",
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"link": null
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},
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{
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"name": "stack",
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"shape": 7,
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"type": "STACK",
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"link": null
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},
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{
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"name": "Expression",
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"type": "STRING,SYNTAX_TREE",
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"widget": {
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"name": "Expression"
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},
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"link": 9
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}
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],
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"outputs": [
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{
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"name": "IMAGE",
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"shape": 6,
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"type": "IMAGE",
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"links": [
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10
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]
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},
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{
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"name": "STACK",
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"type": "STACK",
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"links": null
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}
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],
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"properties": {
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"Node name for S&R": "mrmth_ag_ImageMathNode"
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},
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"widgets_values": [
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"I0*(1-F0)+I1*F0",
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"error",
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0,
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false,
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true
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],
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"widgets_values_named": {
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"Expression": "I0*(1-F0)+I1*F0",
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"length_mismatch": "error",
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"batching": 0,
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"remember_stack": false,
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"use_compute_device": true
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"id": 10,
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"type": "mrmth_ScriptInput",
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"pos": [
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{
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"name": "SYNTAX_TREE",
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"type": "SYNTAX_TREE",
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"links": [
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"# You can also define custom functions. You need to use return keyword on function exit if you will use it's output (forgot what happens when you do not)\ndivide(val1,val2) -> {\n# variables created in function cannot be seen outside but outside variables can be seen and manipulated inside\n# function can call themselves. BE CAREFULL! NOTHING LIKE STACK OVERFLOW EXCEPTION EXIST HERE. I got to recursion depth of 800k before getting bored. If you use a variable outside of a function and then define it in header of a function the outside variable will be shadowed by the one from function definition\nreturn val1/val2;\n};\ndivide(V0,2)\n# Notice that the colors are more saturated. That means previous code returned image with values > 1 and preview image clamped it for the viewport"
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],
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"widgets_values_named": {
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"script": "# You can also define custom functions. You need to use return keyword on function exit if you will use it's output (forgot what happens when you do not)\ndivide(val1,val2) -> {\n# variables created in function cannot be seen outside but outside variables can be seen and manipulated inside\n# function can call themselves. BE CAREFULL! NOTHING LIKE STACK OVERFLOW EXCEPTION EXIST HERE. I got to recursion depth of 800k before getting bored. If you use a variable outside of a function and then define it in header of a function the outside variable will be shadowed by the one from function definition\nreturn val1/val2;\n};\ndivide(V0,2)\n# Notice that the colors are more saturated. That means previous code returned image with values > 1 and preview image clamped it for the viewport"
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}
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},
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{
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"id": 11,
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"type": "PreviewImage",
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"pos": [
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"flags": {},
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"order": 10,
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"mode": 0,
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"inputs": [
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{
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"name": "images",
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"type": "IMAGE",
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"link": 10
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}
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],
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"outputs": [
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{
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"name": "images",
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"type": "IMAGE",
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"links": []
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}
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